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  • In 1 gm of a solid, there are 5\times 10^{21} atoms. If one electron is removed from everyone of 0.01% atoms of the solid, the charge gained

In 1 gm of a solid, there are 5\times 10^{21} atoms. If one electron is removed from everyone of 0.01% atoms of the solid, the charge gained by the solid is (given that electronic charge is 1.6\times 10^{-19}C  )

Option 1)  + 0.08 C

Option 2)  + 0.8 C

Option 3)  - 0.08 C

Option 4)  - 0.8 C

Answers (1)

As we learned

Quantization of charge -

Charge on any body will be some integral multiple of e.

- wherein

Q=\pm ne

n = 1, 2, 3, ......

To calculate charge, we will apply formula Q = ne for this, we must have number of electrons. Here, number of electrons n=.01\; ^{0}/_{0}\; \; of \; 5\times 10^{21}

i.e   n=\frac{5\times 10^{21}\times .01}{100}=5\times 10^{21}\times10^{-4}=5\times 10^{17}

So   Q=5\times 10^{17}\times 1.6\times 10^{-19}=8\times 10^{-2}=0.08\; C

Since electrons have been removed, charge will be positive i.e Q = + 0.08 C

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lovekush

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