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In a solvent 50 \% of an acid HA dimerizes and the rest dissociates. The van't Hoff factor of the acid is_____ \times 10^{-2}.
(Round off to the nearest integer)
 

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The dissociation and association processes are given as

\\\begin{matrix}\mathrm{HA} & \rightleftharpoons &\mathrm{H^+} &+&\mathrm{A^-} \\ \mathrm{1-\alpha -\beta } & &\mathrm{\alpha } &&\alpha \end{matrix}

\\\begin{matrix}\mathrm{HA} & \rightleftharpoons &\mathrm{\left (HA \right )_2} \\ \mathrm{1-\alpha -\beta } & &\mathrm{\frac{\beta}{2}} \end{matrix}

Given,

\alpha=0.5, \beta=0.5

Thus, Vant Hoff factor

= 2\alpha +\frac{B}{2}

\begin{aligned} &=1+\frac{0.5}{2} \\ &=1.25 \\ &=125 \times 10^{-2} \end{aligned}

Hence, the correct answer is 125.

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sudhir.kumar

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