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  • In an interference experiment using waves of same amplitude, path difference between the waves at a point on the screen is

In an interference experiment using waves of same amplitude, path difference between the waves at a point on the screen is \mathrm{\lambda / 4.} The ratio of intensity at this point to that at the central bright fringe is:

Option: 1

1


Option: 2

0.5


Option: 3

1.5


Option: 4

2.0


Answers (1)

best_answer

From \mathrm{I_R=I_1+I_2+2 \sqrt{I_1 I_2} \cos \phi,}

Here, \mathrm{\phi=\frac{2 \pi}{\lambda} \times \frac{\lambda}{4}=\frac{\pi}{2}}

\mathrm{ \therefore \quad \mathrm{I}_{\mathrm{R}}=\mathrm{I}+\mathrm{I}+2 \mathrm{I} \cos \frac{\pi}{2}=2 \mathrm{I} }
At the central bright fringe, \mathrm{I_R^{\prime}=4 \mathrm{I}}

\mathrm{ \therefore \frac{\mathrm{I}_{\mathrm{R}}}{\mathrm{I}_{\mathrm{R}}^{\prime}}=\frac{2 \mathrm{I}}{4 \mathrm{I}}=0.5 }

Posted by

Shailly goel

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