An open vessel at 27o C is heated until two fifth of the air (assumed as an ideal gas ) in it has escaped from the vessel. Assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is : (in K)

Answers (1)

Ideal Gas Law in terms of density -

PM=d RT

- wherein

where

d - density of gas

P - Pressure

R - Gas Constant

T - Temperature

M - Molar Mass

 

Saturated Vapour Pressure -

When equilibrium is attained between vapor and liquid kept in a partially filled beaker , the vapour pressure at that temperature is called saturated vapor pressure.

As we have learned in gaseous state

we know \frac{2}{5} air escaped for vessel,\therefore \frac{3}{5} air reamain

in vessel.

P,V constant

n_{1}T_{1}=n_{2}T_{2}

n_{1}\left ( 300 \right )=\left ( \frac{3}{5}n _{1} \right )T_{2}\Rightarrow T_{2}=500K

 

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