Finds the least distance of the point (3,16) from the circle + +4x-8y-5=0
The equation of the given circle is
The given circle has its centre at (-2,4) and has radius (r) of 5 units
Distance between the given point and centre of the circle is d
The least distance of the point (3,16) from the circle + +4x-8y-5=0 is d - r = 13 - 5 = 8 units