, its Euler form is?
As we have learnt in
Euler form of complex number -
The polar form of complex number z=r(cos ? + i sin ?), in Euler form (cos ? + i sin ?) part of the polar form of complex numbers is represented by eiΘ .
eiΘ = cos? + isin? and e-iΘ = cos? - isin?
Euler forms make algebra very simple for complex numbers. Any complex number can be expressed as
we simplify z, for that we normalize the denominator
Now we see it lies in the 4th quadrant, so the argument is going to be -ve.
First we find r = |z| = 4·2=8
Correct option is (d)
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