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Moment of inertia of solid cylinder mass M, length L and radius R about its own axis is
Option: 1
$MR^{2}$

Option: 2
$ML^{2}$

Option: 3
$\frac{MR^{2}}{2}$

Option: 4
$\frac{ML^{2}}{12}$

Answers (1)

best_answer

Moment of inertia for solid cylinder -

$I=\frac{1}{2} MR^{2}$

- wherein

About axis passing through central line.

MOI about its own axis is $\frac{MR^{2}}{2}$

Posted by

Shailly goel

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