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In a coil of resistance 10\Omega, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil in weber is:

  • Option 1)

    8

  • Option 2)

    2

  • Option 3)

    6

  • Option 4)

    4

 

Answers (1)

best_answer

 

Induced Charge -

dq= i.dt= frac{-N}{R}frac{dphi }{dt}.dt

dq= frac{-N}{R}dphi

 

- wherein

Induced Charge time independent

 

 \Delta \Phi =R.\Delta q

\Delta q= Amount of charge passes through the coil

\Delta q= Area under graph=\frac{1}{2}\times 4\times 0.1=0.2\ c

\therefore \Delta \Omega =10\times 0.2 wb=2wb

 


Option 1)

8

This is incorrect option

Option 2)

2

This is correct option

Option 3)

6

This is incorrect option

Option 4)

4

This is incorrect option

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