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  • Need clarity, kindly explain! (I) (II)H –– N - - - N - - - NIn hydrogen azide (above) the bond orders of bonds (I) and (II) are :

             (I)      (II)

H –– N - - - N - - - N

In hydrogen azide (above) the bond orders of bonds (I) and (II) are :

  • Option 1)

         (I)              (II)

    < 2\; \; \; \; \; \; \; > 2

     

     

     

  • Option 2)

    > 2\; \; \; \; \; \; \; < 2

  • Option 3)

    > 2\; \; \; \; \; \; \; > 2

  • Option 4)

    < 2\; \; \; \; \; \; \; < 2

 

Answers (2)

As we learned 

 

Bond Order -

Bond order is defined as one half the difference between the number of electrons present in the bonding and the antibonding orbitals.

- wherein

Bond \:Order=\frac{N_{b}-{N_{a}}}{2}

 

 

 


Option 1)

     (I)              (II)

< 2\; \; \; \; \; \; \; > 2

 

 

 

Option 2)

> 2\; \; \; \; \; \; \; < 2

Option 3)

> 2\; \; \; \; \; \; \; > 2

Option 4)

< 2\; \; \; \; \; \; \; < 2

Posted by

Vakul

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