Get Answers to all your Questions

header-bg qa


The energy of an electron in first Bohr orbit of H-  atom is -13.6 eV. The energy value of electron in the excited state of Li2+ is :

 

  • Option 1)

    -27.2 eV

  • Option 2)

    30.6 eV

  • Option 3)

    -30.6 eV

  • Option 4)

    27.2 eV

 

Answers (2)

best_answer

As we discussed in the concept

Total energy of elctron in nth orbit -

E_{n}= -13.6\: \frac{z^{2}}{n^{2}}eV

Where z is atomic number

-

 

 E_{n} = 13.6 \times \frac{3^{2}}{2^{2}}

E_{n} = -30.6

 

Answer 3

 

 


Option 1)

-27.2 eV

Incorrect option

Option 2)

30.6 eV

Incorrect option

Option 3)

-30.6 eV

Correct option

Option 4)

27.2 eV

Incorrect option

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE