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Out of TiF_{6}^{2-}, CoF_{6}^{3-}, Cu_{2}Cl_{2} and NiCl_{4}^{2-}(Z of Ti=22, Co=27, Cu=29, Ni=28), the colourless species are:

  • Option 1)

    Cu_{2}Cl_{2} and NiCl_{4}^{2-}

  • Option 2)

    TiF_{6}^{2-} and Cu_{2}Cl_{2}

  • Option 3)

    CoF_{6}^{3-} and NiCl_{4}^{2-}

  • Option 4)

    TiF_{6}^{2-} and CoF_{6}^{3-}

 

Answers (1)

best_answer

As we learned in concept

Diamagnetism -

When substance unaffected by a magnetic field or the central metal atom doesn't have unpaired e- called Diamagnetic substance or character.

- wherein

eg\ \;Sc^{+++}\Rightarrow 3d^{\circ }9s^{2}

No unpaired e-

 

 Any species where central atom has no unpaired e- config of Ti4+:[Ar]3do 4so 

 

Cu2 Cl2 , e- config of Cu+ = [Ar] 3d10 4so

therefore, no unpaired e- s in Cu+  

therefore, [TiF62] and Cu2 Cl2 are colourless

therefore, solution is 2


Option 1)

Cu_{2}Cl_{2} and NiCl_{4}^{2-}

incorrect

Option 2)

TiF_{6}^{2-} and Cu_{2}Cl_{2}

correct

Option 3)

CoF_{6}^{3-} and NiCl_{4}^{2-}

incorrect

Option 4)

TiF_{6}^{2-} and CoF_{6}^{3-}

incorrect

Posted by

prateek

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