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  • Need explanation for: - Limit , continuity and differentiability - JEE Main-9

Let f(x) = x+1  \forall x\epsilon R  and g(x) = x^{2}-3x+2   \forall x\epsilon R  then number of points of discontinuty of \frac{f(x)}{g(x)}   equals 

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As we have learned

Properties of Continuous function -

If   f,\:g   are two continuous functions at a point a of their common domain D.Then  f\pm g   fg are continuous at  a  and if   g(a)\neq 0  then 

 \frac{f}{g}      is also continuous at  x = a.

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\frac{f(x)}{g(x)}=\frac{x+1}{x^{2}-3x+2}   which is not defined when {x^{2}-3x+2}=0

\Rightarrow x=1,2  so discomtinous at 2 points  

 

 

 

 

 

 


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