The volume of gas A is twice than that of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are :

  • Option 1)

    2P_{A}=3P_{B}

  • Option 2)

    3P_{A}=2P_{B}

  • Option 3)

    P_{A}=2P_{B}

  • Option 4)

    P_{A}=3P_{B}

Answers (1)
A admin

@com 

 

Compressibility Factor -

\dpi{100} Z=\frac{V_{real}}{V_{ideal}}

-

 

 

Compressibility Factor -

at  low pressures, all gases have Z less than 1.

-

As we  know from ideal gas equation

Pv=ZnRT= P= \frac{ZnRT}{V} atconstant T and mol P\propto \frac{Z}{V}

THere for \frac{P_{A}}{P_{B}}= \frac{Z_{A}}{Z_{B}}\times \frac{V_{B}}{V_{A}}= \left ( \frac{3}{1} \right )\times \left ( \frac{1}{2} \right )= \frac{3}{2}

\therefore 2P_{A}= 3P_{B}

 

 


Option 1)

2P_{A}=3P_{B}

Option 2)

3P_{A}=2P_{B}

Option 3)

P_{A}=2P_{B}

Option 4)

P_{A}=3P_{B}

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