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  • Neutron is placed in a uniform magnetic field of  with velocity of 5 m/s making an

Neutron is placed in a uniform magnetic field of 5 \times 10^{-2}T with velocity of 5 m/s making an angle of 60^{\circ} with \vec{B}. Find the force on the neutron.

Option: 1

12.5 \times 10^{-4}N


Option: 2

2.5 \times 10^{-2}N


Option: 3

0


Option: 4

10 N


Answers (1)

best_answer

As we learned

Magnetic force if q=0 -

F=qVB\sin \theta

F=0q = 0

-

F=qVB\sin \theta     if q = 0

F=0

 

Posted by

Suraj Bhandari

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