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- Number of gm of oxygen in 32.2 g Na2SO4.10H2O is
Number of gm of oxygen in 32.2 g Na2SO4.10H2O is ?
Answers (1)
No. of oxygen atoms in one molecule =4+10=14
Thus moles of oxygen in n moles of compound=n*14
Molar mass of Na2SO4.10H2O=46+32+64+180=322g/mol
Thus
Thus moles of O=
So weight is
3229 = 32.2/322 = O.lrno/s 16 = 22.49
View full answer
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