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Number of ways in which 10 students can be divided equally into two group is 

Option: 1

124 


Option: 2

126 


Option: 3

128 


Option: 4

130 


Answers (1)

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The number of ways in which 2n different things can be divided equally into two group is \frac{(2n)!}{2!(n!)^{2}}.

So, number of ways = \frac{10 !}{(5!)^2\times 2 !} = 126

 

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HARSH KANKARIA

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