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Number of ways in which 1440 can be resolved into product of two positive integers is 

Option: 1

15 


Option: 2

16 


Option: 3

17 


Option: 4

18 


Answers (1)

best_answer

As we have learned

The number of ways in which n can be resolved as a product of two factors.

\Rightarrow\ \; \frac{1}{2}(1+\alpha_{1})(1+\alpha_{2})........(1+\alpha_{k}) for n=p_{1}^{\alpha_1}p_{2}^{\alpha_2}..........p_{k}^{\alpha_k}

 

Now,

 1440 = 2 ^5 \times 3 ^2 \times 5 ^1

The required number of = \frac{1}{2}(5+1)(2+1)(1+1)=18

 

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seema garhwal

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