does not exist. Why?
Here in PbI4, Pb has +4 oxidation state. Now the electronic configuration of Pb is [Xe]4f145d106s26p2. So we can see that there is 14 f electrons which have very poor shielding effect. So the effective nuclear charge on the outer s & p electrons are increased. So they are stongly attracted towards nucleus and hence becomes inert. So the Pb4+ becomes unstable and shows stong oxidising property. So it reduced to Pb2+. On the other hand, I- shows high reducing property. So the association of these two ions are quite impossible. Hence PbI4 does not exist
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