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  • Please help! A granite rod of 60 cm length is clampedat its middle point and is set into longitudinal vibrations. The density of granite is 2.7×103 kg/m3 and its Young’s modulus is 9.27×1010 Pa. What will be the fundamental frequenc

A granite rod of 60 cm length is clampedat its middle point and is set into longitudinal vibrations. The density of granite is 2.7×103 kg/m3 and its Young’s modulus is 9.27×1010 Pa. What will be the fundamental frequency of the longitudinal vibrations ?

  • Option 1)

    7.5 kHz
     

  • Option 2)

    5 kHz
     

  • Option 3)

    2.5 kHz
     

  • Option 4)

    10 kHz

 

Answers (1)

best_answer

As we have learned

@1123

@1120

 

\nu _{o}=\frac{v}{2l}=\frac{1}{2l} \cdot \sqrt{\frac{\gamma }{\rho }}=\frac{1}{2\ast 0.6}\sqrt{\frac{9.27*10^{10}}{2.7*10^{3}}}

 

      == 4.9*10^{3} HZ \simeq 5kHZ

 


Option 1)

7.5 kHz
 

This is incorrect

Option 2)

5 kHz
 

This is correct

Option 3)

2.5 kHz
 

This is incorrect

Option 4)

10 kHz

This is incorrect

Posted by

divya.saini

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