# Consider the reversible isothermal expansion of an ideal gas in  closed system at two different temperature T1and T2 (T1 < T2 ). The correct graphical depiction of the dependence of work done (W) on the final volume (V) is:Option 1)Option 2)Option 3)Option 4)

Work Done for Isothermal Reversible Expansion of an ideal gas -

$W= -nRT\ln \frac{V_{f}}{V_{i}}$

$V_{f}> V_{i}$

- wherein

At constant temperature

$P\, \alpha \frac{1}{V}$

$W= -nRT\, \ln \frac{P_{i}}{P_{f}}$

as we know that :

The formula of work for (isothermal)

$W=-nRT\ln \frac{V_{2}}{V_{1}}$

$W=-nRT\ln \frac{V_{f}}{V_{i}}$

$\mid w\mid = nR\left ( \ln V_{f}-\ln V_{i} \right )T$

$\mid w\mid = nRT\ln V_{f}-nRT\ln V_{i}$

$\gamma = mx-c$

So,The inter cept of curve 2 is more negative than curve 1 because slope of curve 2 is more than curve1 in the graph

Option 1)

Option 2)

Option 3)

Option 4)

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