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Low spin complex of d6 - cation in an octahedral field will have the following energy:

(\Deltao = Crystal Field Splitting Energy in an octahedral field,

P = Electron pairing energy)

  • Option 1)

    \frac{-12}{5}\Delta_{\text{o}}+3\text{P}

  • Option 2)

    \frac{-2}{5}\Delta_{\text{o}}+2\text{P}

  • Option 3)

    \frac{-2}{5}\Delta_{\text{o}}+\text{P}

  • Option 4)

    \frac{-12}{5}\Delta_{\text{o}}+\text{P}

 

Answers (1)

best_answer

CFSE=\left [ (-\frac{2}{5}n_{t2g}\times \Delta o) +(\frac{3}{5}n_{eg}\Delta o)+np\right]

-\frac{2\times 6}{5}\Delta o+3p

-\frac{12}{5}\Delta o+3p


Option 1)

\frac{-12}{5}\Delta_{\text{o}}+3\text{P}

This option is correct 

Option 2)

\frac{-2}{5}\Delta_{\text{o}}+2\text{P}

This option is incorrect 

Option 3)

\frac{-2}{5}\Delta_{\text{o}}+\text{P}

This option is incorrect 

Option 4)

\frac{-12}{5}\Delta_{\text{o}}+\text{P}

This option is incorrect 

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Aadil

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