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# Engineering

With the rise in temperature, the  dielectric constant Kof a liquid

  • Option 1)

    Increases                          

  • Option 2)

    Decreases

               

  • Option 3)

     Remains unchanged        

  • Option 4)

    Charges erratically

 

Answers (1)
P Plabita

As we learned

Constant Proportionality (k) -

In S.I

K=\frac{1}{4\pi \varepsilon _{0}}

In C.G.S

K=0

 

 

- wherein

\frac{1}{4\pi \varepsilon _{0}}=9\times 10^{9}    \frac{Nm^{2}}{c^{2}}

 

 With temperature rise, dielectric constant of liquid decreases.

 


Option 1)

Increases                          

Option 2)

Decreases

           

Option 3)

 Remains unchanged        

Option 4)

Charges erratically

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