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  • Please help! In a compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of compound is 108. Molecular formula of compound is

In a compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of compound is 108. Molecular formula of compound is

  • Option 1)

    C_{2}H_{6}N_{2}

  • Option 2)

    C_{3}H_{4}N_{}

  • Option 3)

    C_{6}H_{8}N_{2}

  • Option 4)

    C_{9}H_{12}N_{3}

 

Answers (1)

As we leant,

 

Molecular Formula -

The molecular formula shows the exact number of different types of atoms present in a molecule of a compound.

- wherein

For glucose, empirical formula is CH2O .its molar mass is 180 gram.

n = molar mass/empirical formula mass = 180/30=6

Hence molecular formula= C6H12O6

 

 Molar mass of compound = 108 g

 

Total part by weight = 9+1+3.5 = 13.5

Weight of carbon = \frac{9 \times 108}{13.5} = 72 g

\therefore No. of C atoms = \frac{72}{12} = 6.

Weight of H atoms = \frac{1 \times 108}{13.5} = 8 g

\therefore No. of H atoms = \frac{8}{1} = 8

Weight of N atoms = \frac{3.5 \times 108}{13.5} = 28 g

\therefore No. of N atoms = \frac{28}{14} = 2

\Rightarrow the molecular formula is C6H8N2 .


Option 1)

C_{2}H_{6}N_{2}

Option 2)

C_{3}H_{4}N_{}

Option 3)

C_{6}H_{8}N_{2}

Option 4)

C_{9}H_{12}N_{3}

Posted by

Vakul

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