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Number of points of non diffrentiability of f(x)=\sin (\sin x)+ \tan ^{-1}(\sin x) will be

  • Option 1)

    0

  • Option 2)

    1

  • Option 3)

    2

  • Option 4)

    infinite

 

Answers (1)

best_answer

As we have learned

Properties of differentiable functions -

The composition of a differentiable function is a differentiable functions.

-

 

 \sin (\sin x)  is composition of sin x with sin x so it will  be diffrentiable \forall n\epsilon R 

\tan^{-1} (\sin x)  is compostion of \tan^{-1} x with \sin x (both diffrentiable ) so it will be also diffrentiable \forall n\epsilon R 

so sum of two diffrentiable function will also be diffrentiable for all  n\epsilon R 

 

 

 

 


Option 1)

0

Option 2)

1

Option 3)

2

Option 4)

infinite

Posted by

Himanshu

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