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  • Please help! The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutra

The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is

  • Option 1)

    acetamide

  • Option 2)

    benzamide

  • Option 3)

    urea

  • Option 4)

    thiourea.

 

Answers (1)

As we learnt ,

 

Law of Definite Proportions -

A compound always contains exactly the same propotion of elements by weight

- wherein

CaCO3 contains 40% Ca, 12% C and 48% O by weight irrespective of the source.

 

 Using kjeldahl process to calculate the % of N in organic compound :

Let unreacted 0.1 M ( = 0.2 N ) H2SO4 = V' ml

\therefore , 20 ml of 0.5 M NaOH = V' ml of 0.2 N H2SO4 .

\Rightarrow 20 x 0.5 = V' x 0.2

\Rightarrow V' = 50 ml

used H2SO4 = 100 - 50 ml = 50 ml

\therefore % N = 14 N V/W

where N \rightarrow Normality of H2SO4

             V \rightarrow Volume of H2SO4  used

% N = 1.4 x 0.5 x 50/ 0.30 = 46.67 %

Urea = NH2 / ONH2 = 28 \times \frac{100}{60} = 46.67 %

 


Option 1)

acetamide

Option 2)

benzamide

Option 3)

urea

Option 4)

thiourea.

Posted by

subam

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