The enthalpy of fusion of water is 1.435 kCal/mol. The molar entropy change for the melting of ice at 0^{o}C is:

  • Option 1)

    10.52 cal/(molK)

  • Option 2)

    21.04 cal/(molK)

  • Option 3)

    5.260 cal/(molK)

  • Option 4)

    0.526 cal/(molK)

 

Answers (1)
P Prateek Shrivastava

 

Entropy for phase transition at constant pressure -

\Delta S= \frac{\Delta H_{Transition}}{T}

- wherein

Transition \RightarrowFusion, Vaporisition, Sublimation

\Delta H\RightarrowEnthalpy

\Delta E\RightarrowInternal Energy

T\RightarrowTransitional temperature

 

 molar entropy change=\frac{\Delta Q}{n\Delta T}

        (\Delta s)

\frac{1435}{1\times 273}cal/mole-K=5.26\:cal/mole-K


Option 1)

10.52 cal/(molK)

This solution is incorrect 

Option 2)

21.04 cal/(molK)

This solution is incorrect 

Option 3)

5.260 cal/(molK)

This solution is correct 

Option 4)

0.526 cal/(molK)

This solution is incorrect 

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