# What is the solution of the equation $2^{x}+5^{x}-3^{x}-4^{x}=0?$

Say,$f(x) = 2^x + 3^x + 4^x - 5^x = 0$

For, x <=2, f(x) is positive.

For, x >=3, f(x) is negative.

So, there has to be at least one value of x that is between 2 and 3.

The value of x correct to 2 decimal places is

2.37

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