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A massless rope is fixed at one end as shown in fig. Two boys of masses 40kg and 60kg are moving along the rope. The former climbing up with an accelaration of $2m/s^2$ while later coming down with constant velocity of $5m/s$ . The tension at fixed support will be (g= $10m/s^2$ )

Answers (1)

$T_1=(60*g)$

$T-T_1-40g=40a$

$T=T_1+40g+40a$

$T=600+400+80$

$T=1080N$

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Safeer PP

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