A variable force acted on a body at mass 5 Kg as shown in figure. Where S = displacement of block. Then find the work done by force F from S = 0m to S = 3m.
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Calculating work done
![d W=F d x$ \\ $\int d W=\int F d x$\\ $W=\int_{1}^{3}(s^2+2) d x$\\ $W=\left[\frac{s^{3}}{3}\right]_{1}^{3}+2[s]_{1}^{3}$\\ $W=15- \frac{7}{3} \\$W=12.66 J$](https://learn.careers360.com/latex-image/?d%20W%3DF%20d%20x%24%20%5C%5C%20%24%5Cint%20d%20W%3D%5Cint%20F%20d%20x%24%5C%5C%20%24W%3D%5Cint_%7B1%7D%5E%7B3%7D%28s%5E2+2%29%20d%20x%24%5C%5C%20%24W%3D%5Cleft%5B%5Cfrac%7Bs%5E%7B3%7D%7D%7B3%7D%5Cright%5D_%7B1%7D%5E%7B3%7D+2%5Bs%5D_%7B1%7D%5E%7B3%7D%24%5C%5C%20%24W%3D15-%20%5Cfrac%7B7%7D%7B3%7D%20%5C%5C%24W%3D12.66%20J%24)