A variable force F=\left ( s^{2}+2 \right ) acted on a body at mass 5 Kg as shown in figure. Where S = displacement of block. Then find the work done by force F from S = 0m to S = 3m.

Answers (1)

Calculating work done
d W=F d x$ \\ $\int d W=\int F d x$\\ $W=\int_{1}^{3}(s^2+2) d x$\\ $W=\left[\frac{s^{3}}{3}\right]_{1}^{3}+2[s]_{1}^{3}$\\ $W=15- \frac{7}{3} \\$W=12.66 J$

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