Q

pls solve that..

i am new carrier360 pls help me...........

let A and B has 2 and 4 elements. then no of subsets of A*B having 3 or more elements---

a,219

b,234

c;245

d;240

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Let  A={a,b}

B= {x,y,z}

Total number of elements in A x B = 8

Total number of subsets of A x B = $2^8$ = 256

Number of subsets having 3 or more elements = 256  -  ( no. of subsets having (1 element + 2 elements + 0 elements))

=  256 - (1 null set + 8C2 having two elements + 8C1 having one element)

= 256- (1+28+8) = 219

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