The equilibrium constant for $H_2 (g) + CO_2 (g) \leftrightarrow H_2O(g) + CO(g)$ is 1.80 at 1000^oC. If 1 mole of H₂ and 1 mole of CO₂ are placed in one-liter flask, the final equilibrium concentration of CO at 1000*C will be

A. 0.573 M

B. 0.385 M

C. 5.73 M

D. 0.295 M

Answers (1)

L Lovekush Kumar Saini

$\\\text{The given reaction is }:- \qquad \mathrm{H}_{2}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \\ \text { Initial moles: } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \1 \ \ \ \ \ \ \ \ \quad 1 \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \ \ 0 \\ \text { At eqm: } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \1-\mathrm{x} \ \ \ \ \quad 1-\mathrm{x} \quad \ \ \ \ \ \mathrm{x} \ \ \ \ \ \ \ \ \quad \mathrm{x}$

$\begin{aligned} \mathrm{Now}, \mathrm{K}_{\mathrm{C}} &=\frac{\left[\mathrm{H}_{2} \mathrm{O}\right][\mathrm{CO}]}{\left[\mathrm{H}_{2}\right]\left[\mathrm{CO}_{2}\right]} \\ \mathrm{K}_{\mathrm{C}} &=\frac{\mathrm{x} \cdot \mathrm{x}}{(1-\mathrm{x})(1-\mathrm{x})}=1.8 \\ \Rightarrow \quad & \mathrm{x}^{2}=1.8(1-\mathrm{x})(1-\mathrm{x}) \end{aligned}$

$\\\Rightarrow \quad x=1.34(1-x) & \Rightarrow 2.34 x=1.34 \\ & \Rightarrow x=0.573 \\ \text{So, concentration of }\mathrm{CO}$ at $\mathrm{eq} \mathrm{m}=0.573 \mathrm{M}$$

Exams

Colleges

Predictors

Resources

Quick links

Exams

Colleges

Resources

Colleges

Resources

Exams

Exams

Colleges

Predictor

Resources

Exams

Predictors

Resources

Upcoming Events

Exams

Ranking

Products & Resources

NCERT Solutions

Exams

Country

Resources

Exams

Colleges

Predictors

Resources

Exams

Colleges

Predictors

Resources

Engineering Preparation

Government Jobs

Medical Preparation

Exams

Colleges

Predictors

Resources

Resources

Exams

Colleges

Predictors

Exams

Predictors

Colleges

Resources

Exams

Colleges

Resources

Exams

Resources

The equilibrium constant for is 1.80 at 1000o C. If 1 mole of H2 and 1 mole of CO2 are placed in one-liter flask, the final equilibrium concentration of CO at 1000*C will be A. 0.573 M B. 0.385 M C. 5.73 M D. 0.295 M

Similar Questions

Preparation Products

Knockout JEE Main April 2021

Knockout JEE Main April 2022

Test Series JEE Main April 2021

JEE Main Rank Booster 2021

Knockout BITSAT 2021

Ask Question

Register to post Answer

The equilibrium constant for $H_2 (g) + CO_2 (g) \leftrightarrow H_2O(g) + CO(g)$ is 1.80 at 1000^oC. If 1 mole of H₂ and 1 mole of CO₂ are placed in one-liter flask, the final equilibrium concentration of CO at 1000*C will be

A. 0.573 M

B. 0.385 M

C. 5.73 M

D. 0.295 M