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The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 \Omega is:

  • Option 1)

    1.0 \Omega

  • Option 2)

    0.2 \Omega

  • Option 3)

    0.5 \Omega

  • Option 4)

    0.8 \Omega

 

Answers (1)

best_answer

As we discussed in

I\:=\:\frac{\varepsilon }{R+r}

IR+2r=\varepsilon

given

R=10\omega\:\:\:\:\:\:r=?

\varepsilon =2.1V\:\:\:\:\:\:\:\:\:\:\:\:I=0.24

\therefore \:\:\:0.2\times10+0.2\timesr=2.1\:\:\:\:=> 0.2r=0.1

r=\frac{1}{2}=0.5\omega


Option 1)

1.0 \Omega

This option is incorrect.

Option 2)

0.2 \Omega

This option is incorrect.

Option 3)

0.5 \Omega

This option is correct.

Option 4)

0.8 \Omega

This option is incorrect.

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Plabita

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