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  • Solve! Ejection of the photoelectron from metalin the photoelectric effect experiment canbe stopped by applying 0.5 V when theradiation of 250 nm is used. The workfunction of the metal is :

Ejection of the photoelectron from metal in the photoelectric effect experiment can be stopped by applying 0.5 V when the radiation of 250 nm is used. The work function of the metal is :

  • Option 1)

    4 eV

  • Option 2)

    4.5 eV

  • Option 3)

    5 eV

  • Option 4)

    5.5 eV

 

Answers (2)

As we learned 

 

Photoelectric Effect -

\frac{1}{2}mu^{2}= hv-hv_{0}

- wherein

where

m is the mass of the electron

u is the velocity associated with the ejected electron.

h is plank’s constant.

v is frequency of photon,

v0 is threshold frequency of metal.

 

\lambda = 250 nm = 2500\AA

E =\frac{hc}{\lambda }=\frac{12400}{2500}=4.96eV

K\cdot E\cdot = ltopping potential = 0.5 eV

E=W_{0}+K\cdot E\cdot

4.96=W_{0}+0.5

W_{0}= 4.46eV \approx 4.5eV

 


Option 1)

4 eV

Option 2)

4.5 eV

Option 3)

5 eV

Option 4)

5.5 eV

Posted by

subam

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JEE Main high-scoring chapters and topics

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From ejection photoelectron 

. °. hhv°+K.E.

hv/x=¢+ stopping pl

.°.¢=hc/x-S.P.

=  6.6×10^-34×3×10^8÷250×10^-9×1.6×10^-9-0.5×1.6×10^-10

=   6.6×3÷250×1.6×10^2-0.5

= 4.95-0.5

~ 4.5eV

 

Posted by

Surabhi Tanishq

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