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Evaluate the area under the curve y=sinx from x=0 to x=3\pi/2.

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    3

  • Option 4)

    4

 

Answers (1)

best_answer

As we learnt 

 

Working rule for finding area -

 

If curves lies on both sides of x - axes, add their moduli to get total area

- wherein

Area = |A_{1}|+|A_{2}|+|A_{3}|+|A_{4}|

 

 Area = \int_{0}^{\pi}\sin xdx+\int_{\pi}^{3\pi/2}\sin xdx

         =\left [ -\cos x \right ]^{\pi}_{0}-\left [ -\cos x \right ]^{3\pi/2}_{\pi}

         =2+1=3

 


Option 1)

1

Option 2)

2

Option 3)

3

Option 4)

4

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gaurav

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