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Consider the following reaction:

\small Phenol\overset{Zn\:dust}{\rightarrow}X\xrightarrow[Anhydrous\:AlCl_{3}]{CH_{3}Cl}\:Y

\small \overset{Alkaline\:KMnO_{4}}{\rightarrow}\:Z

The product Z is:

  • Option 1)

    Benzaldehyde

  • Option 2)

    Benzoic Acid

  • Option 3)

    Benzene

  • Option 4)

    Toluene

 

Answers (1)

best_answer

As we learnt in 

Reaction of phenol with zinc dust -

Product form is benzene.

- wherein

C_{6}H_{5}OH+Zn(dust)\rightarrow C_{6}H_{5}+ZnO

 


Option 1)

Benzaldehyde

This is incorrect option

Option 2)

Benzoic Acid

This is correct option

Option 3)

Benzene

This is incorrect option

Option 4)

Toluene

This is incorrect option

Posted by

Aadil

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