In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be :
8 A
10 A
12 A
14 A
As we have learned
In parallel Grouping -
-
Resistance of each bulb of 40 W
Resistance of 15 bulbs = 1210/15 = 242/3
Resistance of 100 W bulb =
Resistance of 5 such bulbs = 485/5
Resistance of fan = = 605
Resistance of 5 such fan = 605 /5
= 121
Resistance of heater =
Equivalent resistance
R = 484 / 25
Option 1)
8 A
Option 2)
10 A
Option 3)
12 A
Option 4)
14 A
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