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The group having isoelectronic species is :

  • Option 1)

    O^{2}^{-} , F^{-} ,Na , Mg^{2}^{+}

  • Option 2)

    O^{-} , F^{-} , Na^{+} , Mg^{2}^{+}

  • Option 3)

    O^{2}^{-} , F^{-} , Na^{+} , Mg^{2}^{+}

  • Option 4)

    O^{-} , F^{-} , Na , Mg^{+}

 

Answers (2)

As we learnt in 

Octet Rule -

Atoms form chemical bond in order to complete their octet i.e eight electrons in their valence shell

-

 

  Number of electron in O2-,F-,Na+ and Mg2+ are same 


Option 1)

O^{2}^{-} , F^{-} ,Na , Mg^{2}^{+}

This option is correct 

Option 2)

O^{-} , F^{-} , Na^{+} , Mg^{2}^{+}

This option is incorrect 

Option 3)

O^{2}^{-} , F^{-} , Na^{+} , Mg^{2}^{+}

This option is incorrect 

Option 4)

O^{-} , F^{-} , Na , Mg^{+}

This option is incorrect 

Posted by

Vakul

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JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Option 3 is correct 

Because here oxygen gains 2 electron and form an atom with 10 protons and electron 

Fluorine gain 1 electron becomes 10 

Sodium loses 1 electron become 10 

Magnesium loses 2 electron becomes 10 

Posted by

Anand singh

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