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  • Solve this problem A magnetic moment of 1.73 BM will be shown by one among the following:

A magnetic moment of 1.73 BM will be shown by one among the following:

  • Option 1)

    [CoCl6]4-

  • Option 2)

    [Cu(NH3)4]2+

  • Option 3)

    [Ni(CN)4]2-

  • Option 4)

    TiCl4

 

Answers (1)

best_answer

On the basis of magnetic moment the number of unpaired electrons is one

\left [ Cu(NH_{3})_{4} \right ]^{2+} has only one unpaired electron 


Option 1)

[CoCl6]4-

This option is incorrect 

Option 2)

[Cu(NH3)4]2+

This option is correct 

Option 3)

[Ni(CN)4]2-

This option is incorrect 

Option 4)

TiCl4

This option is incorrect 

Posted by

Plabita

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