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  • Solve this problem - A process has. Out of the values given below , choose the minimum temperature above which the pro - Chemical Thermodynamics - JEE Main

A process has  \Delta H=200\: Jmol^{-1}\: \: and\: \: \Delta S=40\: JK^{-1}mol^{-1}. Out  of the values given below , choose the minimum temperature above which the process will be spontaneous :

  • Option 1)

    20 K

  • Option 2)

    12 K

  • Option 3)

    5 K

     

  • Option 4)

    4 K

Answers (1)

best_answer

 

Spontanous process -

\Delta G=\Delta H-T\Delta S

 

- wherein

For spontanouse process \Delta G must be negative.

As we have learned in Gibbs free energy

\Delta G = \Delta H - T\Delta S

T = \frac{\Delta H}{\Delta S} = \frac{200}{40} = 5K

 


Option 1)

20 K

Option 2)

12 K

Option 3)

5 K

 

Option 4)

4 K

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