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  • Solve this problem The de-Broglie wavelength of neutron in thermal equilibrium at tempreture T is

The de-Broglie wavelength of neutron in thermal equilibrium at tempreture T is

  • Option 1)

    \frac{30}{\sqrt{T}}A^{\circ}

  • Option 2)

    \frac{3.08}{\sqrt{T}}A^{\circ}

  • Option 3)

    \frac{0.308}{\sqrt{T}}A^{\circ}

  • Option 4)

    \frac{0.0308}{\sqrt{T}}A^{\circ}

 

Answers (1)

best_answer

As we discussed in concept

De - Broglie wavelength with charged particle -

lambda = frac{h}{sqrt{2mE}}= frac{h}{sqrt{2mE}}

lambda = frac{h}{sqrt{2mqv}}
 

- wherein

E ightarrow kinetic: energy: o! f particle

q ightarrow charged : particle

 

 \lambda\:=\:\frac{h}{p}=\frac{h}{\sqrt{2m}E}=\frac{h}{\sqrt{2m}.(\frac{3}{2}KT)}=\frac{h}{\sqrt{3mK}T}=\frac{30}{\sqrt{T}}A^{\circ}

 


Option 1)

\frac{30}{\sqrt{T}}A^{\circ}

This option is correct.

Option 2)

\frac{3.08}{\sqrt{T}}A^{\circ}

This option is incorrect.

Option 3)

\frac{0.308}{\sqrt{T}}A^{\circ}

This option is incorrect.

Option 4)

\frac{0.0308}{\sqrt{T}}A^{\circ}

This option is incorrect.

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Plabita

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