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  • Solve this problem There are two equipotential surface as shown in figure. The distance between them is r. The charge of –q coulomb is taken from the surface A to B, the resultant work done will be

There are two equipotential surface as shown in figure. The distance between them is r. The charge of –q coulomb is taken from the surface A to B, the resultant work done will be

  • Option 1)

    W = \frac{1}{4\pi\epsilon_0 } \frac{q}{r}

  • Option 2)

    W = \frac{1}{4\pi\epsilon_0 } \frac{q}{r^2}

  • Option 3)

    W = - \frac{1}{4\pi\epsilon_0 } \frac{q}{r^2}

  • Option 4)

    W = zero

 

Answers (1)

best_answer

As we learned

Equipotential Surface -

The Direction of electric field is Perpendicular to equipotential surface.

-

 

 

 

The work done is given by W = q(V_2 - V_1) = 0 because of equipotential  surface. Both are connected to each other. Potential will be same.


Option 1)

W = \frac{1}{4\pi\epsilon_0 } \frac{q}{r}

Option 2)

W = \frac{1}{4\pi\epsilon_0 } \frac{q}{r^2}

Option 3)

W = - \frac{1}{4\pi\epsilon_0 } \frac{q}{r^2}

Option 4)

W = zero

Posted by

Avinash

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