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The favorable condition for NH3 is 

Option: 1

Low temperature, high pressure


Option: 2

High temperature, low pressure


Option: 3

Low temperature, low pressure


Option: 4

High temperature, high pressure


Answers (1)

best_answer

As we have learnt,

N_{2} + 3H_{2}\rightleftharpoons 2NH_{3}+\Delta H

Reaction is exothermic so favorable condition is low temperature.

Now, on increasing the pressure, the equilibrium shifts in the direction of less number of gaseous moles. Since the number of gaseous moles decrease on the right hand side, the favaourable condition will be high pressure.

Therefore, option (1) is correct.

Posted by

Irshad Anwar

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