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  • Starting from rest, the acceleration of a particle is a=2(t-1). The velocity of the particle at t=5s is:

Starting from rest, the acceleration of a particle is a=2(t-1). The velocity of the particle at t=5s is:

Answers (1)

It is known that, 

\frac{dv}{dt} = a

So, 

\frac{dv}{dt} = 2(t-1)
\int_0^v dv= \int _0^52(t-1)dt
                =[t^2-2t]_0^5
                  = (25 - 10) - (0)
                  = 15 m/s

Hence the velocity of partice at t = 5 sec is 15 m/s

Posted by

lovekush

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