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  • Stuck here, help me understand: A ballon with mass 'm' descending down with an acceleration 'a' (where a < g). How much mass should be removed from itso that it starts moving up with an acceleration 'a' ?

A ballon with mass 'm' descending down with an acceleration 'a' (where a < g). How much mass should be removed from it so that it starts moving up with an acceleration 'a' ?

  • Option 1)

    \frac{2\text{ma}}{\text{g}+\text{a}}

  • Option 2)

    \frac{2\text{ma}}{\text{g}-\text{a}}

  • Option 3)

    \frac{\text{ma}}{\text{g}+\text{a}}

  • Option 4)

    \frac{\text{ma}}{\text{g}-\text{a}}

 

Answers (1)

best_answer

As we learnt in

Reaction or Normal Force -

A force which is perpendicular to the surface in contact.

- wherein

                      

 

 

 

mg-B=ma        .............(1)

B-(m-m_{o})g=(m-m_{0})a    ............(ii)

Eq. (i) + Eq.(ii)

mg - B + B - (m - m0)g = ma + (m - mo)g = ma 

mo=\frac{2ma}{g+a}


Option 1)

\frac{2\text{ma}}{\text{g}+\text{a}}

Correct 

Option 2)

\frac{2\text{ma}}{\text{g}-\text{a}}

Incorrect

Option 3)

\frac{\text{ma}}{\text{g}+\text{a}}

Incorrect

Option 4)

\frac{\text{ma}}{\text{g}-\text{a}}

Incorrect

Posted by

prateek

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