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  • Stuck here, help me understand: For a reaction between A and B the order with respect to A is 2 and the order with respect to B is 3. The concentrations of both A and B are doubled, the rate will increase by a factor of:

For a reaction between A and B the order with respect to A is 2 and the order with respect to B is 3. The concentrations of both A and B are doubled, the rate will increase by a factor of:

  • Option 1)

    10

  • Option 2)

    12

  • Option 3)

    16

  • Option 4)

    32

 

Answers (1)

best_answer

 

Rate of Law = Dependence of Rate on Concentration -

The representation of rate of a reaction in terms of concentration of the reactants is known as Rate Law

or

The Rate Law is the expression in which reaction rate is given in terms of molar concentration of reactants with each term raised to some power, which may/maynot be equal to stoichiometric of the reacting species in a balanced chemical equation 

- wherein

Formula: aA+bB\rightarrow cC+dD

              Rate=\frac{dR}{dT}

              =\alpha [A]^{x}.[B]^{y}

             =k[A]^{x}.[B]^{y}

 K= rate constant

 

 Rate, r_{1}=k\left [ A \right ]^{2}\left[ B \right ]^{3}

On doubling the concentration, we have

r_{2}=k\left [ 2A \right ]^{2}\left[ 2B \right ]^{3}

=32k\left [ A \right ]^{2}\left[ B \right ]^{3}= 32r_{1}

 


Option 1)

10

Incorrect option

Option 2)

12

Incorrect option

Option 3)

16

Incorrect option

Option 4)

32

Correct option

Posted by

Plabita

View full answer

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