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  • Stuck here, help me understand: - In the reaction of oxalate with permannganate in acidic medium, the number of electrons involved in - Redox Reaction and Electrochemistry - JEE Main

In the reaction of oxalate with permannganate in acidic medium, the number of electrons involved in producing one molecule of CO_{2} is:

  • Option 1)

    10

  • Option 2)

    2

  • Option 3)

    1

  • Option 4)

    5

Answers (1)

best_answer

 

Balancing of Redox Reactions -

Oxidation number method

- wherein

1. Write the correct formula for each reactant and product.

2. Identify atom whose oxidation number is changed.

3. Calculate increase / decrease in oxidation number per atom and for the entire molecule / ion in which it occures.

4. Add H^{+}/OH^{-} on appropriate side so that the total ionic charges of reactants and products are equal.

5. Make numbers of hydrogen atoms in the expression on the two sides equal by adding H_{2}O to reactant or product

 

As we have learned ,

When oxalate reacts with permanganate in acidic medium.

2\overset{+7}{Mn}O_{4} + 5C_{2}O_{4}^{2-} + 16H^{+} \rightarrow 2\overset{+2}{Mn}^{2+} + 10CO_{2} + 8H_{2}O

We know that 10 e- transfer for 10 molecules of CO2 . So per molecule of CO2 transfer of e- is '1' .

 


Option 1)

10

Option 2)

2

Option 3)

1

Option 4)

5

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