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  • Stuck here, help me understand: - Surface Chemistry - JEE Main

If x gram of gas is adsorbed by m gram of absorbent at pressure P, the plot of  \frac{x}{m}  versus logP is linear. The Slope of the plot is : 

(n and k are constants and n > 1)

  • Option 1)

    2k

  • Option 2)

    log\; k

  • Option 3)

    n

  • Option 4)

    \frac{1}{n}

 

Answers (1)

best_answer

As we have learnt

 

Freundlich isotherm graph -

\frac{x}{m}= K\cdot p^{1/n}

This curve indicate that at fixed pressure there is a decrease in physical adsorption with increase in temperature

- wherein

Surface Chemistry Image 1

 

 \frac{x}{m} =K\times P^{\frac{1}{n}} \\*\Rightarrow \log \frac{x}{m} = \log K + \frac{1}{n}\log P

 

 


Option 1)

2k

Option 2)

log\; k

Option 3)

n

Option 4)

\frac{1}{n}

Posted by

Aadil

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