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  • Stuck here, help me understand: The correct combination is :

The correct combination is :

  • Option 1)

    \left [ Ni\left ( CN \right )_{4} \right ]^{2-}-tetrahedral ;

    \left [ Ni\left ( CO \right )_{4} \right ]-paramagnetic

     

     

     

     

     

     

     

     

     

  • Option 2)

    \left [ NiCl_{4} \right ]^{2-}-paramagnetic;

    \left [ Ni\left ( CO \right )_{4} \right ]-tetrahedral

  • Option 3)

    \left [ NiCl_{4} \right ]^{2-}-square-planar;

    \left [ Ni\left ( CN \right )_{4} \right ]^{2-}-paramagnetic

  • Option 4)

    \left [ NiCl_{4} \right ]^{2-}-diamagnetic;

    \left [ Ni\left ( CO \right )_{4} \right ]-square-planar

 

Answers (2)

best_answer

As we learned 

 

Weak field Ligand -

These are the ligands which do not pair the electron in inner d-orbital.

- wherein

For example: N_{2}O, F^{-}, Cl^{-} etc    

 

 

Strong Field Ligand -

These are the ligands which pair the electron in inner d-orbital and makes required d-orbitals empty/available. 

- wherein

For example: CO, CN etc

 

 

Ni^{+2}\rightarrow \left [ Ar \right ]3d^{8},4S^{0},4p^{0}                         Ni\left ( o \right )\left [ Ar \right ]3d^{8},4S^{2},4p^{0}

Cl- is weak field ligand                                             CO is strong field ligand

(no pairing of electron)                                    \left [ Ar \right ]3d^{10} 4S^{0}4p^{0}

                                                                                              Sp^{3}

                                                                                    tetrahedral 

 

 


Option 1)

\left [ Ni\left ( CN \right )_{4} \right ]^{2-}-tetrahedral ;

\left [ Ni\left ( CO \right )_{4} \right ]-paramagnetic

 

 

 

 

 

 

 

 

 

Option 2)

\left [ NiCl_{4} \right ]^{2-}-paramagnetic;

\left [ Ni\left ( CO \right )_{4} \right ]-tetrahedral

Option 3)

\left [ NiCl_{4} \right ]^{2-}-square-planar;

\left [ Ni\left ( CN \right )_{4} \right ]^{2-}-paramagnetic

Option 4)

\left [ NiCl_{4} \right ]^{2-}-diamagnetic;

\left [ Ni\left ( CO \right )_{4} \right ]-square-planar

Posted by

Plabita

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