25 ml of the given HCl solution requires 30 mL of 0.1 M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of 0.2 M aqueous NaOH solution ?

  • Option 1)

    25 mL

  • Option 2)

    75 mL

  • Option 3)

    12.5 mL

     

  • Option 4)

    50 mL

Answers (1)
A admin

 

Molality -

Molality (m) = (number of moles of solute)/(mass of solvent in kg)

 

- wherein

It is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.

eq. of HCl = eq. of Na_{2}CO_{3}

25\times N=2\times 0.1\times 30

HCl=0.24 N

eq. of HCl = eq. of NaOH

V\times 0.24 = 30\times 0.2

V=25 ml

 

 

Number of Moles -

No of moles = given mass of substance/ molar mass of substance

-

 

 

Molar Mass -

The mass of one mole of a substance in grams is called its molar mass.

- wherein

 Molar mass of water = 18 g mol-1

 

 

 


Option 1)

25 mL

Option 2)

75 mL

Option 3)

12.5 mL

 

Option 4)

50 mL

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