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  • Tell me? A Carnot’s engine works as a refrigeratorbetween 250 K and 300 K. It receives500 cal heat from the reservoir at the lowertemperature. The amount of work donein each cycle to operate the refrigeratoris :

A Carnot’s engine works as a refrigerator
between 250 K and 300 K. It receives
500 cal heat from the reservoir at the lower
temperature. The amount of work done
in each cycle to operate the refrigerator
is :

  • Option 1)

    420 J

  • Option 2)

    772 J

  • Option 3)

    2100 J

  • Option 4)

    2520 J

 

Answers (2)

As we learned 

 

Coefficient of performance (β) -

\beta = \frac{Q_{2}}{Q_{1}-Q_{2}}= \frac{T_{2}}{T_{1}-T_{2}}
 

- wherein

T_{1}> T_{2}

For a perfect refrigerator \beta \rightarrow \infty

 

 

Coefficient of performance (β) -

\beta = \frac{Q_{2}}{Q_{1}-Q_{2}}= \frac{T_{2}}{T_{1}-T_{2}}
 

- wherein

T_{1}> T_{2}

For a perfect refrigerator \beta \rightarrow \infty

 

 Coefficient of performance = \frac{T_{1}}{T_{1}-T_{2}}=\frac{Q_{1}}{W}=\frac{Q_{2}}{W}+1

\frac{300}{50}=\frac{500}{W}+1 or \frac{500}{W} = 5

\Rightarrow W = 100 cal

420 J


Option 1)

420 J

Option 2)

772 J

Option 3)

2100 J

Option 4)

2520 J

Posted by

Vakul

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